(13x^2-34x+12)/(3x-2)=x-1

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Solution for (13x^2-34x+12)/(3x-2)=x-1 equation: 



(13x^2-34x+12)/(3x-2)=x-1

We move all terms to the left:

(13x^2-34x+12)/(3x-2)-(x-1)=0



Domain of the equation: (3x-2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=2

x!=2/3

x!=2/3

x∈R



We get rid of parentheses

(13x^2-34x+12)/(3x-2)-x+1=0

We multiply all the terms by the denominator


(13x^2-34x+12)-x*(3x-2)+1*(3x-2)=0

We multiply parentheses

-3x^2+(13x^2-34x+12)+2x+1*(3x-2)=0

We get rid of parentheses

-3x^2+13x^2-34x+2x+1*(3x-2)+12=0

We add all the numbers together, and all the variables

10x^2-32x+1*(3x-2)+12=0

We move all terms containing x to the left, all other terms to the right

10x^2-32x+1*(3x-2)=-12

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